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The question asks:

**Jika 3, x, dan 9 merupakan tiga suku pertama barisan geometri, tentukan nilai x.**

This means: "If 3, \( x \), and 9 are the first three terms of a geometric sequence, determine the value of \( x \)."

In a geometric sequence, the ratio between consecutive terms is constant. Let's denote the common ratio by \( r \). Thus, the following relationships hold:

\[
\frac{x}{3} = r \quad \text{and} \quad \frac{9}{x} = r
\]

Since both equal \( r \), we can set these two equations equal to each other:

\[
\frac{x}{3} = \frac{9}{x}
\]

Now, let's solve this equation for \( x \):

\[
x^2 = 3 \times 9
\]
\[
x^2 = 27
\]
\[
x = \sqrt{27} = 3\sqrt{3}
\]

Therefore, the value of \( x \) is \( 3\sqrt{3} \).

Would you like more details or have any questions about this? Here are some related problems you could explore:

1. What is the common ratio \( r \) in this geometric sequence?
2. Can you find the next term in this geometric sequence?
3. How do you generalize the formula for the \( n \)-th term in a geometric sequence?
4. What is the sum of the first \( n \) terms of a geometric sequence?
5. How would the solution change if the geometric sequence was decreasing?

**Tip:** Always check if the terms in a geometric sequence follow the correct ratio between consecutive terms to avoid calculation mistakes.

Jika 3, x, dan 9 merupakan tiga suku pertama barisan geometri, tentukan nilai x.

Solve for x in the geometric sequence where the first three terms are 3, x, and 9. This detailed step-by-step guide uses the concept of geometric progression and the common ratio formula, suitable for students in Grades 9-12.

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