Math Problem Statement

Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving the plane region about the x-axis: y = 6 - x, y = 0, x = 7.

Solution

We are asked to use the shell method to find the volume of the solid formed by revolving the region enclosed by the curves:

y=6x,y=0,x=7y = 6 - x, \quad y = 0, \quad x = 7 around the x-axis.

Shell Method Overview:

The shell method revolves vertical slices around the axis of rotation. For rotation around the x-axis, the volume is given by:

V=2πabradius(x)×height(x)dxV = 2\pi \int_{a}^{b} \text{radius}(x) \times \text{height}(x) \, dx

  • Radius of the shell: The distance from the x-axis, which is yy.
  • Height of the shell: The horizontal distance, which is along the x-axis, is represented by the function xx as the height depends on the curve y=6xy = 6 - x.
  • Limits of integration: From y=0y = 0 to y=6y = 6 since the curve starts at y=0y = 0 and ends at y=6y = 6.

We will express xx in terms of yy, from the equation y=6xy = 6 - x, we have x=6yx = 6 - y.

Defining the Integral:

Now applying the shell method, we write the integral for the volume:

V=2π06y(7(6y))dyV = 2\pi \int_{0}^{6} y \cdot (7 - (6 - y)) \, dy Simplifying the height expression:

V=2π06y(1+y)dyV = 2\pi \int_{0}^{6} y \cdot (1 + y) \, dy

Solving the Integral:

We can now expand the integrand:

V=2π06(y+y2)dyV = 2\pi \int_{0}^{6} (y + y^2) \, dy

Now, solve the integral:

V=2π[y22+y33]06V = 2\pi \left[ \frac{y^2}{2} + \frac{y^3}{3} \right]_{0}^{6}

Substitute the limits:

V=2π[622+633]V = 2\pi \left[ \frac{6^2}{2} + \frac{6^3}{3} \right]

V=2π[362+2163]V = 2\pi \left[ \frac{36}{2} + \frac{216}{3} \right]

V=2π[18+72]V = 2\pi \left[ 18 + 72 \right]

V=2π×90=180πV = 2\pi \times 90 = 180\pi

Final Answer:

The volume of the solid generated by revolving the region around the x-axis is 180π\boxed{180\pi}.

Would you like more details on the shell method or this solution?

Here are some related questions to deepen your understanding:

  1. How does the shell method differ from the disk/washer method?
  2. What if the region were rotated around the y-axis instead of the x-axis?
  3. How does the choice of axis of rotation affect the setup of the integral?
  4. Can we use the disk method to solve this problem? How would it be set up?
  5. What are the advantages of using the shell method in certain problems?

Tip: Always verify whether you need to solve for xx in terms of yy (or vice versa) when setting up shell method integrals, as this depends on the axis of revolution.

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Math Problem Analysis

Mathematical Concepts

Calculus
Volume of Solids of Revolution
Shell Method

Formulas

V = 2π ∫ (radius) × (height) dx

Theorems

Shell Method

Suitable Grade Level

College Calculus