Math Problem Statement

Given that 1+2/3x)^n (3+ nx)^2 = 9 + 84x + ..., find the value of n.

Solution

We are given the expression:

(1+23x)n(3+nx)2=9+84x+\left( 1 + \frac{2}{3x} \right)^n (3 + nx)^2 = 9 + 84x + \dots

We need to find the value of nn. Let's solve it step by step.

Step 1: Expand the terms

The expression involves two terms to expand:

  1. (1+23x)n\left( 1 + \frac{2}{3x} \right)^n
  2. (3+nx)2(3 + nx)^2

Step 2: Expand (1+23x)n\left( 1 + \frac{2}{3x} \right)^n

We can use the binomial expansion to expand (1+23x)n\left( 1 + \frac{2}{3x} \right)^n. The binomial expansion of (1+a)n(1 + a)^n is given by:

(1+a)n=1+na+n(n1)2!a2+(1 + a)^n = 1 + n \cdot a + \frac{n(n-1)}{2!} \cdot a^2 + \cdots

For a=23xa = \frac{2}{3x}, we get the following first few terms:

(1+23x)n=1+n23x+\left( 1 + \frac{2}{3x} \right)^n = 1 + n \cdot \frac{2}{3x} + \cdots

Step 3: Expand (3+nx)2(3 + nx)^2

Now, expand (3+nx)2(3 + nx)^2:

(3+nx)2=9+6nx+n2x2(3 + nx)^2 = 9 + 6nx + n^2 x^2

Step 4: Multiply the two expansions

Now, multiply the two expanded expressions:

(1+n23x+)(9+6nx+n2x2+)\left( 1 + n \cdot \frac{2}{3x} + \cdots \right) \cdot \left( 9 + 6nx + n^2 x^2 + \cdots \right)

Let's focus on the terms up to xx, since the right-hand side of the equation is given as 9+84x+9 + 84x + \cdots.

  • The constant term: 1×9=91 \times 9 = 9
  • The xx-term: 1×6nx=6nx1 \times 6nx = 6nx and n23x×9=18n3x=6nn \cdot \frac{2}{3x} \times 9 = \frac{18n}{3x} = 6n (note that this term contributes to the coefficient of xx).

Thus, the coefficient of xx from the product of the two terms is:

6n+6n=12n6n + 6n = 12n

We know that the coefficient of xx in the final expression is 84, so we set:

12n=8412n = 84

Step 5: Solve for nn

Solve for nn:

n=8412=7n = \frac{84}{12} = 7

Thus, the value of nn is 7\boxed{7}.


Would you like further details on any of the steps, or do you have any questions about this solution?

Here are some related questions you can explore:

  1. How do you perform a binomial expansion for higher-order terms?
  2. What is the significance of each term in the binomial expansion?
  3. How do you multiply two binomial expansions correctly?
  4. How can we generalize the method for higher powers or different types of expressions?
  5. Can you calculate the coefficient of x2x^2 in this problem?

Tip: When expanding binomials, keep track of each term and ensure you only combine like terms (e.g., powers of xx).

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Math Problem Analysis

Mathematical Concepts

Binomial Expansion
Algebra
Polynomial Expansion

Formulas

(1 + a)^n = 1 + n*a + n(n-1)/2!*a^2 + ...
(3 + nx)^2 = 9 + 6nx + n^2x^2

Theorems

Binomial Theorem
Multiplying Polynomial Expressions

Suitable Grade Level

Grades 11-12