Math Problem Statement

It is given that the HCF of two numbers is 72 and LCM of those two numbers is 4536. Both the numbers are greater than their HCF. Find the two numbers

Solution

Given that the Highest Common Factor (HCF) of two numbers is 72, and their Lowest Common Multiple (LCM) is 4536, we need to find the two numbers.

Let the two numbers be aa and bb.

We know that the product of the two numbers is equal to the product of their HCF and LCM:

a×b=HCF×LCMa \times b = \text{HCF} \times \text{LCM}

Substituting the given values:

a×b=72×4536a \times b = 72 \times 4536

Let's calculate this:

a×b=326592a \times b = 326592

So, the product of the two numbers is 326592.

Now, we know that a=72×xa = 72 \times x and b=72×yb = 72 \times y, where xx and yy are co-prime (since xx and yy will have no common factors other than 1).

Then,

[ 72 \times

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Math Problem Analysis

Mathematical Concepts

Number Theory
Factors
Multiples

Formulas

Product of HCF and LCM = Product of Numbers

Theorems

Fundamental Theorem of Arithmetic

Suitable Grade Level

High School