The velocity $v(t)$ of the object is found by taking the derivative of the position function $s(t)$. The velocity function is:

$v(t) = t^2 - 7t + 6$

To find when the velocity is zero, we solve:

$t^2 - 7t + 6 = 0$

The solutions are $t = 1$ second and $t = 6$ seconds.

Would you like more details or have any questions?

Here are 5 related questions to consider:

1. How do you interpret the physical meaning of the velocity being zero?
2. What is the object's acceleration at $t = 1$ and $t = 6$?
3. How do you find the maximum or minimum position of the object?
4. What is the object's position at $t = 1$ and $t = 6$?
5. Can you determine when the object is moving forward or backward?

Tip: The critical points where velocity is zero often indicate where an object changes direction or stops momentarily.