Math Problem Statement

If sn= Sn =(-1)^n (3+ 1/ 2^n) then find sup Sn and inf Sn by using definition

Solution

Given the sequence Sn=(1)n(3+12n)S_n = (-1)^n \left( 3 + \frac{1}{2^n} \right), we are tasked with finding the supremum (supSn\sup S_n) and infimum (infSn\inf S_n) using the formal definition of these concepts.

Key Observations:

  1. The sequence has alternating signs due to the (1)n(-1)^n factor.

    • When nn is odd, Sn=(3+12n)S_n = - \left( 3 + \frac{1}{2^n} \right).
    • When nn is even, Sn=+(3+12n)S_n = + \left( 3 + \frac{1}{2^n} \right).
  2. As nn \to \infty, the term 12n\frac{1}{2^n} approaches 0, meaning that:

    • Sn3S_n \to 3 for even nn.
    • Sn3S_n \to -3 for odd nn.

Thus, the sequence approaches values around 3 and -3.

Behavior of SnS_n:

  • When nn is even, Sn=3+12nS_n = 3 + \frac{1}{2^n}, which means the terms are slightly larger than 3 but approach 3 as nn increases.
  • When nn is odd, Sn=(3+12n)S_n = - \left( 3 + \frac{1}{2^n} \right), so these terms are slightly smaller than 3-3 and approach 3-3 as nn increases.

Supremum and Infimum:

  • Supremum (supSn\sup S_n): The supremum is the least upper bound of the sequence. Since the even-indexed terms of the sequence are always slightly larger than 3 but get arbitrarily close to 3, the largest value the sequence can take is just above 3.

    Therefore, supSn=3+122=3.25\sup S_n = 3 + \frac{1}{2^2} = 3.25, which occurs at n=2n = 2, and no larger value exists.

  • Infimum (infSn\inf S_n): The infimum is the greatest lower bound of the sequence. The odd-indexed terms are slightly smaller than -3 but approach 3-3 as nn increases. So, the smallest value the sequence can take is just below 3-3.

    Therefore, infSn=(3+121)=3.5\inf S_n = - \left( 3 + \frac{1}{2^1} \right) = -3.5, which occurs at n=1n = 1, and no smaller value exists.

Conclusion:

  • supSn=3.25\sup S_n = 3.25.
  • infSn=3.5\inf S_n = -3.5.

Would you like a more detailed explanation of the steps, or do you have any further questions?


Here are some related questions to explore:

  1. How is the behavior of a sequence affected by alternating signs?
  2. What is the difference between the supremum and the maximum of a sequence?
  3. How do the bounds of a sequence relate to its long-term behavior?
  4. What is the impact of the decay term 12n\frac{1}{2^n} on the sequence?
  5. How would you compute limits for different types of sequences?

Tip: Always analyze the behavior of even- and odd-indexed terms separately when dealing with alternating sequences.

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Math Problem Analysis

Mathematical Concepts

Sequences and Series
Supremum and Infimum
Limits
Alternating Series

Formulas

Sn = (-1)^n (3 + 1 / 2^n)
Supremum (\sup S_n)
Infimum (\inf S_n)

Theorems

Definition of Supremum and Infimum
Limit of Sequences

Suitable Grade Level

Undergraduate - First Year Calculus