To find the slope of the line in this graph, we need to use the formula for slope:

$\text{slope} = \frac{\text{change in } y}{\text{change in } x} = \frac{\Delta y}{\Delta x}$

The $y$-axis represents the "Position (km)" and the $x$-axis represents "Time (s)".

Step-by-Step Process:

1. From the graph, we can identify two clear points:

   • At $t = 0$ seconds, position $= 0$ km.
   • At $t = 5$ seconds, position $= 1.25$ km.

2. Now calculate the change in position ($\Delta y$) and the change in time ($\Delta x$): $\Delta y = 1.25 \text{ km} - 0 \text{ km} = 1.25 \text{ km}$ $\Delta x = 5 \text{ s} - 0 \text{ s} = 5 \text{ s}$

3. Using the slope formula: $\text{slope} = \frac{1.25 \text{ km}}{5 \text{ s}} = 0.25 \text{ km/s}$

Thus, the slope of the line is 0.25 km/s.

Would you like further details on any part of this solution? Here are 5 related questions you might explore:

1. How does the slope of a line relate to velocity in a position-time graph?
2. What would happen if the slope was negative in this type of graph?
3. How can we determine average velocity from a position-time graph?
4. How would the graph look if the object was at rest for some time?
5. What other types of motion could be represented on a position-time graph?

Tip: The steeper the slope in a position vs. time graph, the faster the object's velocity!