To calculate the slope of the line shown in the graph, we can follow the formula for the slope $m$:

$m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}$

Where $(x_1, y_1)$ and $(x_2, y_2)$ are two points on the line. From the image, let's extract two clear points:

• Point 1: $(0, 0)$ (where the line crosses the origin).
• Point 2: $(5.0, 15.0)$.

Now we apply the formula:

$m = \frac{15.0 - 0}{5.0 - 0} = \frac{15.0}{5.0} = 3.0 \, \text{m/s}$

The slope of the line is $3.0 \, \text{m/s}$.

Do you want further details or have any questions? Here are some related questions to explore:

1. How does changing the slope affect the motion described by the graph?
2. What does a negative slope represent in a position-time graph?
3. How can you determine velocity from the slope in different sections of a non-linear graph?
4. How do units of the axes influence the interpretation of the slope?
5. What is the significance of the slope in terms of uniform motion?

Tip: For motion graphs, the slope of a position-time graph represents the object's velocity.