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To find \(\sin(\angle B)\) in the given triangle \(ABC\), we need to understand the relationship between the sides of the triangle and the sine function. In a right triangle, \(\sin(\angle B)\) is defined as the ratio of the length of the side opposite the angle \(B\) to the hypotenuse.

From the image, the triangle \(ABC\) has:
- \(AB = 8\) (opposite to \(\angle B\))
- \(AC = 17\) (hypotenuse)
- \(BC = 15\) (adjacent to \(\angle B\))

Using the sine function definition:
\[ \sin(\angle B) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{AB}{AC} = \frac{8}{17} \]

Thus, \(\sin(\angle B)\) is \(\frac{8}{17}\).

**Answer: C) \(\frac{8}{17}\)**

Would you like any further details or have any questions?

Here are some related questions you might find interesting:
1. What is \(\cos(\angle B)\) in the given triangle?
2. What is \(\tan(\angle B)\) in the given triangle?
3. How do you find \(\sin(\angle A)\) in the given triangle?
4. How can you verify the Pythagorean theorem with the given side lengths?
5. What is the length of the altitude from point \(C\) to hypotenuse \(AB\)?
6. How do you find \(\cos(\angle A)\) in the given triangle?
7. How do you find \(\tan(\angle A)\) in the given triangle?
8. What are the other trigonometric ratios (cot, sec, csc) for \(\angle B\)?

**Tip:** In right triangles, the trigonometric functions sine, cosine, and tangent can be easily found using the sides' lengths relative to the specific angle.

Learn how to find sin(angle B) in Triangle ABC with sides AB = 8, AC = 17, and BC = 15 using the sine function definition. This problem involves trigonometric concepts and the Pythagorean theorem, suitable for high school students.

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