To find $\sin(\angle B)$ in the given triangle $ABC$, we need to understand the relationship between the sides of the triangle and the sine function. In a right triangle, $\sin(\angle B)$ is defined as the ratio of the length of the side opposite the angle $B$ to the hypotenuse.

From the image, the triangle $ABC$ has:

• $AB = 8$ (opposite to $\angle B$)
• $AC = 17$ (hypotenuse)
• $BC = 15$ (adjacent to $\angle B$)

Using the sine function definition: $\sin(\angle B) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{AB}{AC} = \frac{8}{17}$

Thus, $\sin(\angle B)$ is $\frac{8}{17}$.

Answer: C) $\frac{8}{17}$

Would you like any further details or have any questions?

Here are some related questions you might find interesting:

1. What is $\cos(\angle B)$ in the given triangle?
2. What is $\tan(\angle B)$ in the given triangle?
3. How do you find $\sin(\angle A)$ in the given triangle?
4. How can you verify the Pythagorean theorem with the given side lengths?
5. What is the length of the altitude from point $C$ to hypotenuse $AB$?
6. How do you find $\cos(\angle A)$ in the given triangle?
7. How do you find $\tan(\angle A)$ in the given triangle?
8. What are the other trigonometric ratios (cot, sec, csc) for $\angle B$?

Tip: In right triangles, the trigonometric functions sine, cosine, and tangent can be easily found using the sides' lengths relative to the specific angle.