To solve for the sine ratio of angle $\Theta$, we use the definition of sine in a right triangle:

$\sin(\Theta) = \frac{\text{opposite side}}{\text{hypotenuse}}$

From the triangle:

• The side opposite $\Theta$ is $AB = 15$.
• The hypotenuse is $BC = 17$.

Thus, the sine ratio is:

$\sin(\Theta) = \frac{15}{17}$

Final Answer:

$\sin(\Theta) = \frac{15}{17}$

Would you like a detailed breakdown of how sine is defined or applied in trigonometry?

Related Questions:

1. What are the cosine and tangent ratios for angle $\Theta$?
2. How do you calculate the sine of $\Theta$ as a decimal approximation?
3. What are the properties of a right triangle that make trigonometric ratios possible?
4. How can you verify if $\sin(\Theta)$ is correct using the Pythagorean Theorem?
5. What is the reciprocal of the sine ratio, and how is it used?

Tip:

Remember the acronym SOHCAHTOA: Sine = Opposite / Hypotenuse, Cosine = Adjacent / Hypotenuse, Tangent = Opposite / Adjacent!