Math Problem Statement

Find f Subscript xx​, f Subscript xy​, Subscript f Subscript yx​, and f Subscript yy for the following function.​ (Remember, f Subscript yx means to differentiate with respect to y and then with respect to​ x.) ​f(x, ​y)equals10yln x

Solution

Given the function f(x,y)=10yln(x)f(x, y) = 10y \ln(x), we need to find the following partial derivatives:

  1. fxxf_{xx} (the second partial derivative of ff with respect to xx),
  2. fxyf_{xy} (the partial derivative of ff first with respect to xx and then with respect to yy),
  3. fyxf_{yx} (the partial derivative of ff first with respect to yy and then with respect to xx), and
  4. fyyf_{yy} (the second partial derivative of ff with respect to yy).

Let's start with the first-order partial derivatives:

1. First-Order Partial Derivatives

fxf_x (the partial derivative of ff with respect to xx):

fx=x(10yln(x))f_x = \frac{\partial}{\partial x} \left( 10y \ln(x) \right) Since 10y10y is treated as a constant with respect to xx, we have: fx=10y1x=10yxf_x = 10y \cdot \frac{1}{x} = \frac{10y}{x}

fyf_y (the partial derivative of ff with respect to yy):

fy=y(10yln(x))f_y = \frac{\partial}{\partial y} \left( 10y \ln(x) \right) Since ln(x)\ln(x) is treated as a constant with respect to yy, we have: fy=10ln(x)f_y = 10 \ln(x)

2. Second-Order Partial Derivatives

fxxf_{xx} (the second partial derivative of ff with respect to xx):

fxx=x(10yx)f_{xx} = \frac{\partial}{\partial x} \left( \frac{10y}{x} \right) Taking the derivative of 10yx\frac{10y}{x} with respect to xx: fxx=10yx2f_{xx} = -\frac{10y}{x^2}

fxyf_{xy} (the partial derivative of fxf_x with respect to yy):

fxy=y(10yx)f_{xy} = \frac{\partial}{\partial y} \left( \frac{10y}{x} \right) Taking the derivative of 10yx\frac{10y}{x} with respect to yy: fxy=10xf_{xy} = \frac{10}{x}

fyxf_{yx} (the partial derivative of fyf_y with respect to xx):

fyx=x(10ln(x))f_{yx} = \frac{\partial}{\partial x} \left( 10 \ln(x) \right) Taking the derivative of 10ln(x)10 \ln(x) with respect to xx: fyx=10xf_{yx} = \frac{10}{x} (Note that fxy=fyxf_{xy} = f_{yx}, which is expected due to Clairaut's theorem for mixed partial derivatives.)

fyyf_{yy} (the second partial derivative of ff with respect to yy):

fyy=y(10ln(x))f_{yy} = \frac{\partial}{\partial y} \left( 10 \ln(x) \right) Since 10ln(x)10 \ln(x) is independent of yy, we have: fyy=0f_{yy} = 0

Summary of Results

  • fxx=10yx2f_{xx} = -\frac{10y}{x^2}
  • fxy=10xf_{xy} = \frac{10}{x}
  • fyx=10xf_{yx} = \frac{10}{x}
  • fyy=0f_{yy} = 0

Would you like more details or have any questions? Here are 5 related questions for further exploration:

  1. How do we use the second-order partial derivatives in determining the concavity of a function?
  2. What is the significance of mixed partial derivatives being equal (i.e., fxy=fyxf_{xy} = f_{yx})?
  3. How would the partial derivatives change if the function were f(x,y)=10xln(y)f(x, y) = 10x \ln(y) instead?
  4. Can you find the critical points of the function f(x,y)=10yln(x)f(x, y) = 10y \ln(x)?
  5. How do partial derivatives relate to the gradient of a function in multivariable calculus?

Tip: In multivariable calculus, the equality fxy=fyxf_{xy} = f_{yx} is guaranteed under certain conditions (such as continuity of second-order derivatives) and is known as Schwarz's theorem or Clairaut's theorem.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Partial Derivatives
Second-Order Partial Derivatives

Formulas

Partial derivative formula
Clairaut's theorem

Theorems

Clairaut's theorem (Equality of mixed partial derivatives)

Suitable Grade Level

Advanced Undergraduate