Math Problem Statement

For a binomial distribution X~Bin(n,p), suppose n=5. If P(X=0)=0.00032, what is p? In your response, provide a detailed explanation of your steps and reasoning at each step.

Solution

In this problem, we are given that XX follows a binomial distribution with parameters n=5n = 5 and an unknown probability of success pp, and we need to determine the value of pp given that P(X=0)=0.00032P(X = 0) = 0.00032.

Step 1: The binomial distribution formula

The probability mass function (PMF) for a binomial distribution XBin(n,p)X \sim \text{Bin}(n, p) is given by the formula: P(X=k)=(nk)pk(1p)nkP(X = k) = \binom{n}{k} p^k (1-p)^{n-k} where:

  • nn is the number of trials,
  • pp is the probability of success on a single trial,
  • kk is the number of successes,
  • (nk)\binom{n}{k} is the binomial coefficient, which represents the number of ways to choose kk successes from nn trials.

In our case, we are interested in P(X=0)P(X = 0), which is the probability of having zero successes.

Step 2: Apply the formula for P(X=0)P(X = 0)

Using the binomial distribution formula for P(X=0)P(X = 0): P(X=0)=(50)p0(1p)5P(X = 0) = \binom{5}{0} p^0 (1-p)^{5} Simplifying the terms: P(X=0)=1(1p)5P(X = 0) = 1 \cdot (1-p)^{5} So, the probability of getting zero successes is simply: P(X=0)=(1p)5P(X = 0) = (1-p)^{5}

Step 3: Set up the equation

We are given that P(X=0)=0.00032P(X = 0) = 0.00032, so we can set up the equation: (1p)5=0.00032(1-p)^{5} = 0.00032

Step 4: Solve for pp

To solve for pp, first take the fifth root of both sides of the equation: 1p=0.0003251 - p = \sqrt[5]{0.00032} Now, calculate the fifth root of 0.00032. We can do this by raising 0.00032 to the power of 15\frac{1}{5}: 1p=(0.00032)151 - p = (0.00032)^{\frac{1}{5}}

We compute the value of (0.00032)15(0.00032)^{\frac{1}{5}}.

1p0.21 - p \approx 0.2

Step 5: Solve for pp

Now, solve for pp by subtracting 0.2 from 1: p=10.2p = 1 - 0.2 p=0.8p = 0.8

Final Answer:

Thus, the value of pp is 0.8\boxed{0.8}.


Would you like more details or have any questions about the steps?

Here are 5 related questions for practice:

  1. What is P(X=1)P(X = 1) for this binomial distribution with p=0.8p = 0.8?
  2. How would you calculate the expected value of XX for XBin(5,0.8)X \sim \text{Bin}(5, 0.8)?
  3. What is the probability that X3X \geq 3 for this binomial distribution?
  4. What is the variance of the distribution XBin(5,0.8)X \sim \text{Bin}(5, 0.8)?
  5. How does the binomial distribution change as nn increases for a fixed pp?

Tip: When solving for unknowns in probability equations, taking roots is often necessary—make sure to review your exponent rules!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution
Exponents

Formulas

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)
P(X=0) = (1-p)^n

Theorems

Binomial Theorem

Suitable Grade Level

Grades 10-12