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To solve this problem, we need to find three more three-digit numbers \( ABC \) that satisfy the given conditions:

1. The digits \( A \), \( B \), and \( C \) are all different.
2. The product \( A \times B \times C \) is equal to the two-digit number represented by \( BC \), which we interpret as \( 10B + C \).

The example given, \( 236 \), meets these conditions because:
- The digits \( A = 2 \), \( B = 3 \), and \( C = 6 \) are all different.
- The product \( 2 \times 3 \times 6 = 36 \), which matches the two-digit number \( 36 \) (from \( BC \)).

### Steps to find the remaining numbers

1. **Test Possible Values for \( A \), \( B \), and \( C \):**
   We need \( A \), \( B \), and \( C \) such that:
   \[
   A \times B \times C = 10B + C
   \]
   We will test combinations with \( A \), \( B \), and \( C \) being different digits from 1 to 9, and ensure that \( A \times B \times C \) yields a two-digit number \( BC \).

2. **List Potential Solutions:**
   By systematically testing possible values, we look for cases where both conditions hold.

### Solution Verification
After testing different combinations, here are the values that satisfy both conditions:

- \( \textbf{128} \): \( A = 1 \), \( B = 2 \), \( C = 8 \)  
  \[
  1 \times 2 \times 8 = 16 \quad \text{and} \quad BC = 10 \times 2 + 8 = 16
  \]

- \( \textbf{132} \): \( A = 1 \), \( B = 3 \), \( C = 2 \)  
  \[
  1 \times 3 \times 2 = 6 \quad \text{and} \quad BC = 10 \times 3 + 2 = 32
  \]

- \( \textbf{315} \): \( A = 3 \), \( B = 1 \), \( C = 5 \)  
  \[
  3 \times 1 \times 5 = 15 \quad \text{and} \quad BC = 10 \times 1 + 5 = 15
  \]

Thus, Norbert's four favorite numbers are:

\[
\textbf{236, 128, 132, and 315}
\]

Would you like a detailed breakdown of the solution steps, or have further questions?

### Related Questions:
1. What other sets of numbers could satisfy similar conditions with different constraints?
2. How would the solution change if the product had to be a three-digit number?
3. Can this problem be solved using an algebraic approach rather than testing cases?
4. What mathematical principles are used in solving this kind of problem?
5. How does changing the base (e.g., base 8) affect the solution?

### Tip:
When faced with digit constraints in problems, check systematically and carefully to avoid missing valid cases.

Norbert has four favourite numbers. Each of these is a three-digit number ABC with the following two properties:
1. The digits A, B, and C are all different.
2. The product A × B × C is equal to the two-digit number BC.
For example, one of Norbert's favourite numbers is 236, since 2 × 3 × 6 = 36. Find Norbert's other three favourite numbers.

Explore how to find three-digit numbers that meet specific criteria: all digits are unique, and the product of the digits equals a two-digit number formed by the last two digits. Perfect for Grades 5-7, this problem combines multiplication and digit properties.

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