Math Problem Statement

Suppose z is a complex number satisfying z−(1/z)=4+4i . Find the length (or modulus) of z+(1/z) .

Solution

Given the complex number zz satisfying the equation

z1z=4+4i,z - \frac{1}{z} = 4 + 4i,

we need to find the modulus (or length) of z+1zz + \frac{1}{z}.

Step 1: Let z=a+biz = a + bi, where aa and bb are real numbers.

The reciprocal 1z\frac{1}{z} can be expressed as:

1z=1a+bi=abia2+b2\frac{1}{z} = \frac{1}{a + bi} = \frac{a - bi}{a^2 + b^2}

Thus, the equation z1z=4+4iz - \frac{1}{z} = 4 + 4i becomes:

(a+bi)abia2+b2=4+4i(a + bi) - \frac{a - bi}{a^2 + b^2} = 4 + 4i

Step 2: Separate the equation into real and imaginary parts.

Let's express the equation as:

a+bi(aa2+b2ba2+b2i)=4+4ia + bi - \left(\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i\right) = 4 + 4i

Equating real and imaginary parts:

Real part:

aaa2+b2=4a - \frac{a}{a^2 + b^2} = 4

Imaginary part:

b+ba2+b2=4b + \frac{b}{a^2 + b^2} = 4

Step 3: Simplify and solve for aa and bb.

Real part equation:

a(11a2+b2)=4a\left(1 - \frac{1}{a^2 + b^2}\right) = 4

This simplifies to:

a(a2+b21a2+b2)=4a\left(\frac{a^2 + b^2 - 1}{a^2 + b^2}\right) = 4

Imaginary part equation:

b(1+1a2+b2)=4b\left(1 + \frac{1}{a^2 + b^2}\right) = 4

This simplifies to:

b(a2+b2+1a2+b2)=4b\left(\frac{a^2 + b^2 + 1}{a^2 + b^2}\right) = 4

Step 4: Find z+1zz + \frac{1}{z}.

Now, we calculate z+1zz + \frac{1}{z}:

z+1z=(a+bi)+(aa2+b2ba2+b2i)z + \frac{1}{z} = (a + bi) + \left(\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i\right)

=(a+aa2+b2)+(bba2+b2)i= \left(a + \frac{a}{a^2 + b^2}\right) + \left(b - \frac{b}{a^2 + b^2}\right)i

Step 5: Calculate the modulus of z+1zz + \frac{1}{z}.

The modulus is given by:

z+1z=(a+aa2+b2)2+(bba2+b2)2\left| z + \frac{1}{z} \right| = \sqrt{\left(a + \frac{a}{a^2 + b^2}\right)^2 + \left(b - \frac{b}{a^2 + b^2}\right)^2}

We know from the given condition:

z1z2=4+4i2=42+42=32\left| z - \frac{1}{z} \right|^2 = |4 + 4i|^2 = 4^2 + 4^2 = 32

Thus, the modulus of z+1zz + \frac{1}{z} is also 32=42\sqrt{32} = 4\sqrt{2}.

Final Answer:

The modulus of z+1zz + \frac{1}{z} is 424\sqrt{2}.

Would you like to see more details, or have any questions? Here are 5 related questions to consider:

  1. What is the general method to find the modulus of a complex number?
  2. How do you find the modulus of a complex expression like z1zz - \frac{1}{z}?
  3. Can you derive a general formula for z+1z|z + \frac{1}{z}| in terms of z|z|?
  4. What is the geometric interpretation of the modulus of a complex number?
  5. How does the modulus change when a complex number is inverted (i.e., 1z\frac{1}{z})?

Tip: When solving complex equations, separating real and imaginary parts is often key to finding solutions.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Reciprocal of Complex Numbers
Modulus of Complex Numbers

Formulas

Complex number representation
Reciprocal of a complex number
Modulus of a complex number

Theorems

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Suitable Grade Level

High School