Math Problem Statement

If 𝑓: 𝑅 βˆ’ {2} 𝑅 is a function defined by 𝑓(π‘₯) = then find f-1 :range of 𝑓 𝑅 βˆ’ {2}.

Solution

To find the inverse fβˆ’1f^{-1} of a function f(x)f(x) and determine its range, we need to have a complete definition of f(x)f(x), particularly the expression on the right side of f(x)=…f(x) = \ldots.

Without the expression, it's difficult to provide an exact answer, but I can guide you through the general steps you would take:

  1. Identify the Expression: Start by ensuring we know the exact formula of f(x)f(x) given on the right side of the equation.

  2. Set y=f(x)y = f(x): To find the inverse function, set y=f(x)y = f(x) and solve for xx in terms of yy.

  3. Solve for xx in terms of yy: Rearrange the equation to express xx as a function of yy. This new expression will represent fβˆ’1(y)f^{-1}(y).

  4. Determine the Range of ff: Since the domain of ff is Rβˆ’{2}\mathbb{R} - \{2\}, you’d need to consider any limitations or asymptotes in f(x)f(x) to find its range.

  5. Adjust Domain of fβˆ’1f^{-1}: Ensure the domain of fβˆ’1f^{-1} corresponds to the range of f(x)f(x).

If you provide the specific formula for f(x)f(x), I can give you the exact solution for fβˆ’1f^{-1} and determine the range of ff. Would you like further clarification on these steps?


Here are five related questions for exploration:

  1. How can we find the domain and range of a function analytically?
  2. What conditions must a function satisfy to be invertible?
  3. How does removing values from the domain affect the inverse of a function?
  4. What are common techniques for solving for the inverse of rational functions?
  5. How does one determine if a function is one-to-one?

Tip: When finding an inverse, always verify that the original function is one-to-one over its domain to ensure the inverse exists.

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Math Problem Analysis

Mathematical Concepts

Functions
Inverse Functions
Domain and Range

Formulas

Inverse Function Formula: f^{-1}(y)

Theorems

One-to-One Property
Existence of Inverse Functions

Suitable Grade Level

Grades 10-12