Math Problem Statement

What is the range of the original function?

Consider the function f(x) = x^2 + 2 for the domain [0, ∞). Find f^(-1)(x), where f^(-1) is the inverse of f. Also state the domain of f^(-1) in interval notation.

Solution

The function given is f(x)=x2+2f(x) = x^2 + 2 with a domain of [0,)[0, \infty).

Step 1: Analyze the range of the function

The range of a function is the set of all possible output values. To find the range of f(x)f(x), we observe that:

  • For x[0,)x \in [0, \infty), the term x2x^2 is non-negative, meaning x20x^2 \geq 0.
  • Thus, f(x)=x2+22f(x) = x^2 + 2 \geq 2.

Since f(x)f(x) is equal to 2 when x=0x = 0, and as xx increases, f(x)f(x) becomes larger, the range of f(x)f(x) is:

Range of f(x)=[2,).\text{Range of } f(x) = [2, \infty).

Do you want further details on how to find the inverse, or do you have any questions about this explanation?

Here are 5 related questions:

  1. How do you find the inverse of a quadratic function?
  2. What is the geometric interpretation of a function's inverse?
  3. Why is the domain restricted to [0,)[0, \infty) for this function?
  4. Can the range of a function affect the existence of its inverse?
  5. How does the range of a function help in determining the domain of its inverse?

Tip: To ensure the existence of an inverse for a function, the function must be one-to-one (bijective), which often requires restricting its domain.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions and Inverses
Domain and Range

Formulas

Inverse function formula: If y = f(x), then x = f^(-1)(y)

Theorems

One-to-one function property

Suitable Grade Level

Grades 11-12