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The problem in the image involves a triangle with a base of 45 cm. It appears the task is to find the height of the triangle. From the handwritten notes, we have the following equations:

1. \( h^2 = \left( \frac{b + h}{2} \right) \)
2. \( h^2 = \frac{45 + h}{2} \)
3. \( h = 22.5 \, \text{cm} \)

It seems that the approach involves equating expressions related to the area or sides of the triangle. The final result obtained is \( h = 22.5 \, \text{cm} \).

Would you like me to confirm the result with a detailed step-by-step explanation, or is there another part of the problem that you would like assistance with? 

### Related Questions
1. How can we derive the formula used for height in this triangle?
2. What is the formula for the area of a triangle?
3. Can the Pythagorean theorem be applied to this problem?
4. What is the significance of the height in a triangle’s properties?
5. How can we find the height using trigonometric ratios?

**Tip:** For triangles, remember that height is always perpendicular to the base.

Find the height of a triangle with a base of 45 cm using the given formula.

Learn how to find the height of a triangle with a base of 45 cm using algebraic methods. This problem covers key concepts from geometry and algebra, including the formula h^2 = (b + h) / 2. Suitable for Grades 7-9.

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