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The problem asks to find the area of a triangle with a base \( b = 15 \) and height \( h = 22 \). The formula for the area of a triangle is:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

Substituting the given values:

\[
\text{Area} = \frac{1}{2} \times 15 \times 22
\]

Let's calculate the area:

\[
\text{Area} = \frac{1}{2} \times 330 = 165
\]

The area of the triangle is **165 square units**.

Would you like more details or have any questions? Here are five related questions to explore further:

1. How does the area of a triangle change if you double the base or the height?
2. Can the height of a triangle ever be outside the triangle itself?
3. How would you calculate the area of a triangle if the height isn't given directly?
4. What are the different ways to express the area of a triangle besides using base and height?
5. How does the Pythagorean theorem relate to right-angled triangles like this one?

**Tip:** Always ensure the base and height are perpendicular when using the area formula for triangles!

What is the area of the triangle with a base of 15 and a height of 22?

Learn how to calculate the area of a triangle with a base of 15 and height of 22 using the formula: (1/2) * base * height. This step-by-step solution explains key geometry concepts. Suitable for Grades 6-8.

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