To solve the formula for $h$, we'll start with the formula for the area of a triangle:

$A = \frac{1}{2}bh$

Where:

• $A$ is the area,
• $b$ is the base,
• $h$ is the height.

Now, let's solve for $h$:

1. Multiply both sides by 2 to eliminate the fraction:

$2A = bh$

2. Divide both sides by $b$ to isolate $h$:

$h = \frac{2A}{b}$

Thus, the height $h$ is:

$h = \frac{2A}{b}$

Let me know if you'd like more details or have any questions!

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Here are 5 related questions to consider:

1. What is the area of a triangle if the base is 10 and height is 5?
2. How would you solve for the base $b$ instead of the height?
3. If the area is 50 and the base is 8, what is the height of the triangle?
4. How would the formula change for a right-angled triangle?
5. How is the area of a parallelogram related to this formula?

Tip: Always remember to use the same units for base and height when calculating the area!