The graph depicts a straight line. To determine the gradient (slope) and y-intercept:

1. Gradient (Slope)

The slope of a line is calculated as: $m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}$

From the graph:

• Two points on the line are $(0, -1)$ (y-intercept) and $(2, 1)$.
• Using these points: $m = \frac{1 - (-1)}{2 - 0} = \frac{2}{2} = 1$

So, the gradient $m = 1$.

2. Y-Intercept

The y-intercept is the point where the line crosses the y-axis. From the graph, the line crosses the y-axis at $y = -1$.

Final Answer:

• Gradient: $m = 1$
• Y-Intercept: $c = -1$

Would you like further explanation or have any questions?

5 Related Questions:

1. How is the gradient related to the steepness of the line?
2. What is the equation of this line in slope-intercept form ($y = mx + c$)?
3. Can you calculate the x-intercept for this line?
4. How would the graph change if the gradient were negative?
5. What are the coordinates of another point on this line?

Tip:

To quickly identify the gradient from a graph, choose two clear points on the line, and use the rise-over-run formula!