To find $f(x + h)$ for the given function $f(x) = 2x - 1$, we simply substitute $x + h$ in place of $x$ in the original function:

$f(x + h) = 2(x + h) - 1$

Now simplify:

$f(x + h) = 2x + 2h - 1$

Thus, $f(x + h) = 2x + 2h - 1$.

Would you like further details or have any questions?

Here are some related questions:

1. How do you find $f(2x)$ for the same function $f(x) = 2x - 1$?
2. What is the difference between $f(x+h)$ and $f(x)$?
3. How does $f(x+h)$ relate to the concept of a derivative?
4. How can you calculate $f(h)$ in this case?
5. What happens when you substitute a negative value for $h$ in $f(x+h)$?

Tip: Understanding how to manipulate function arguments (like $x + h$) is crucial for grasping the fundamentals of calculus and algebraic transformations.