Math Problem Statement

Find all possible functions with the given derivative from the exercises in the image.

Solution

These exercises involve finding the original function yy by integrating the given derivative yy'. Let's go through each exercise, one by one, and solve them by integrating the provided yy'.

Exercise 33:

a. y=xy' = x

y=xdx=x22+Cy = \int x \, dx = \frac{x^2}{2} + C where CC is the constant of integration.

b. y=x2y' = x^2

y=x2dx=x33+Cy = \int x^2 \, dx = \frac{x^3}{3} + C

c. y=x3y' = x^3

y=x3dx=x44+Cy = \int x^3 \, dx = \frac{x^4}{4} + C

Exercise 34:

a. y=2xy' = 2x

y=2xdx=x2+Cy = \int 2x \, dx = x^2 + C

b. y=2x1y' = 2x - 1

y=(2x1)dx=x2x+Cy = \int (2x - 1) \, dx = x^2 - x + C

c. y=3x2+2x1y' = 3x^2 + 2x - 1

y=(3x2+2x1)dx=x3+x2x+Cy = \int (3x^2 + 2x - 1) \, dx = x^3 + x^2 - x + C

Exercise 35:

a. y=1x2y' = -\frac{1}{x^2}

y=1x2dx=1x+Cy = \int -\frac{1}{x^2} \, dx = \frac{1}{x} + C

b. y=11x2y' = 1 - \frac{1}{x^2}

y=(11x2)dx=x+1x+Cy = \int \left(1 - \frac{1}{x^2}\right) \, dx = x + \frac{1}{x} + C

c. y=5+1x2y' = 5 + \frac{1}{x^2}

y=(5+1x2)dx=5x1x+Cy = \int \left(5 + \frac{1}{x^2}\right) \, dx = 5x - \frac{1}{x} + C

Exercise 36:

a. y=12xy' = \frac{1}{2\sqrt{x}}

y=12xdx=x+Cy = \int \frac{1}{2\sqrt{x}} \, dx = \sqrt{x} + C

b. y=1xy' = \frac{1}{\sqrt{x}}

y=1xdx=2x+Cy = \int \frac{1}{\sqrt{x}} \, dx = 2\sqrt{x} + C

c. y=4x1xy' = 4x - \frac{1}{\sqrt{x}}

y=(4x1x)dx=2x22x+Cy = \int \left(4x - \frac{1}{\sqrt{x}}\right) \, dx = 2x^2 - 2\sqrt{x} + C

Exercise 37:

a. y=sin(2t)y' = \sin(2t)

y=sin(2t)dt=12cos(2t)+Cy = \int \sin(2t) \, dt = -\frac{1}{2} \cos(2t) + C

b. y=cos(t2)y' = \cos\left(\frac{t}{2}\right)

y=cos(t2)dt=2sin(t2)+Cy = \int \cos\left(\frac{t}{2}\right) \, dt = 2\sin\left(\frac{t}{2}\right) + C

c. y=sin(2t)+cos(t2)y' = \sin(2t) + \cos\left(\frac{t}{2}\right)

y=(sin(2t)+cos(t2))dt=12cos(2t)+2sin(t2)+Cy = \int \left(\sin(2t) + \cos\left(\frac{t}{2}\right)\right) \, dt = -\frac{1}{2} \cos(2t) + 2\sin\left(\frac{t}{2}\right) + C


Would you like more details on any specific exercise or the steps of integration? Here are 5 questions to explore further:

  1. How can you find the constant CC in an integral if additional conditions are provided?
  2. What are the integration techniques for complex derivatives like 1x\frac{1}{\sqrt{x}}?
  3. How can you apply integration to real-life problems involving motion or growth?
  4. What is the significance of trigonometric integration in physics?
  5. How does the chain rule relate to these types of differentiation problems?

Tip: When integrating, always remember to include the constant of integration CC, as it represents a family of functions!

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Math Problem Analysis

Mathematical Concepts

Differentiation
Integration
Basic algebraic and trigonometric functions

Formulas

y = ∫ y' dx
∫ x^n dx = x^(n+1)/(n+1) + C
∫ sin(x) dx = -cos(x) + C
∫ cos(x) dx = sin(x) + C

Theorems

Fundamental Theorem of Calculus
Power Rule for Integration
Trigonometric Integrals

Suitable Grade Level

Grades 11-12, Early College