A sequence starts with $122$, and each term decreases by $5$. What is the fourth term of the sequence?

The given sequence starts with $ 122 $ and each term decreases by $ 5 $. This is an arithmetic sequence with the first term $ a = 122 $ and a common difference $ d = -5 $.

To find the fourth term, we use the formula for the $ n $-th term of an arithmetic sequence:

\[
a_n = a + (n - 1) \cdot d
\]

For the fourth term ($ n = 4 $):

\[
a_4 = 122 + (4 - 1) \cdot (-5)
\]

\[
a_4 = 122 + 3 \cdot (-5)
\]

\[
a_4 = 122 - 15
\]

\[
a_4 = 107
\]

So, the fourth term of the sequence is $ \boxed{107} $.

Would you like more details or have any questions?

Here are some related questions to consider:

1. What is the 10th term of this sequence?
2. How many terms are there in this sequence until it reaches zero or below?
3. What is the sum of the first 10 terms of this sequence?
4. What is the general formula for the $ n $-th term of this sequence?
5. How does the sequence behave as $ n $ becomes very large?

**Tip:** In an arithmetic sequence, the difference between consecutive terms is always constant.

Learn how to find the fourth term of an arithmetic sequence starting with 122, where each term decreases by 5. This problem covers arithmetic sequence concepts and the nth term formula. Suitable for students in Grades 7-9.

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