The given sequence starts with $125$ and decreases by $10$ at each step. This is an arithmetic sequence with the first term $a = 125$ and a common difference $d = -10$.

To find the eighth term, we use the formula for the $n$-th term of an arithmetic sequence:

$a_n = a + (n - 1) \cdot d$

For the eighth term ($n = 8$):

$a_8 = 125 + (8 - 1) \cdot (-10)$

$a_8 = 125 + 7 \cdot (-10)$

$a_8 = 125 - 70$

$a_8 = 55$

So, the eighth term of the sequence is $\boxed{55}$.

Would you like more details or have any questions?

Here are some related questions to consider:

1. What is the 15th term of this sequence?
2. What is the sum of the first 8 terms of this sequence?
3. How many terms are there in this sequence until it reaches zero or below?
4. What is the formula for the $n$-th term of this sequence?
5. How would the sequence change if the decrease were by $20$ instead of $10$?

Tip: For arithmetic sequences, knowing the first term and common difference allows you to find any term in the sequence easily using the general formula.