To find the fifth term of an arithmetic sequence, we can use the formula:

$a_n = a_1 + (n-1) \times d$

Where:

• $a_n$ is the $n$-th term,
• $a_1$ is the first term,
• $n$ is the term number,
• $d$ is the common difference.

Given:

• $a_1 = 2$
• $d = 5$
• $n = 5$

Substituting these values into the formula:

$a_5 = 2 + (5-1) \times 5$ $a_5 = 2 + 4 \times 5$ $a_5 = 2 + 20 = 22$

So, the fifth term of the arithmetic sequence is $\mathbf{22}$.

Would you like more details or have any questions? Here are some related questions:

1. How do you find the sum of the first 10 terms of this sequence?
2. What is the 10th term of this sequence?
3. Can you derive the general formula for the $n$-th term of this sequence?
4. How would you calculate the 50th term?
5. What happens if the common difference is negative?

Tip: In arithmetic sequences, the difference between any two consecutive terms is always constant.