The problem states that the terms in the sequence increase by the same number each time, making it an arithmetic sequence. The known terms are:

• Term 1 = 3
• Term 5 = 19

Let's determine the common difference, $d$, and use it to find Term 6.

1. In an arithmetic sequence, each term can be expressed as: $T_n = T_1 + (n - 1) \times d$

2. We know: $T_5 = T_1 + (5 - 1) \times d$ Substituting the values: $19 = 3 + 4d$

3. Solving for $d$: $4d = 19 - 3$ $4d = 16$ $d = 4$

4. Now, we use this common difference to find Term 6: $T_6 = T_1 + (6 - 1) \times d$ $T_6 = 3 + 5 \times 4$ $T_6 = 3 + 20 = 23$

Therefore, the value of Term 6 is 23.

Would you like further details, or have any questions?

Here are some related questions:

1. How would you find the 10th term in this sequence?
2. What is the sum of the first six terms in this sequence?
3. How do you verify that this is indeed an arithmetic sequence?
4. What is the general formula for the nth term in this sequence?
5. If the first term was different, how would that affect the sequence?

Tip: In arithmetic sequences, understanding the common difference helps in predicting subsequent terms easily.