Math Problem Statement

FIND THE EQUATION OF EACH CIRCLE IN GENERAL FORM, GIVEN THE FOLLOWING INFORMATION.

  1. A circle with the radius of 2√17 unites with its center (0,-1)

  2. A circle whose center is at (6.-8) with a diameter that is 6√13 units

  3. A circle whose center is at (5,0) and passes through the point (9,3)

Solution

To find the equation of a circle in general form Ax2+Ay2+Dx+Ey+F=0Ax^2 + Ay^2 + Dx + Ey + F = 0, we can start from the standard form of the circle equation (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2, where (h,k)(h,k) is the center and rr is the radius.

Problem 4:

A circle with the radius of 2172\sqrt{17} units with its center (0,1)(0, -1)

  1. Standard Form: (x0)2+(y+1)2=(217)2(x - 0)^2 + (y + 1)^2 = (2\sqrt{17})^2 Simplifying: x2+(y+1)2=417x^2 + (y + 1)^2 = 4 \cdot 17 x2+(y+1)2=68x^2 + (y + 1)^2 = 68

  2. Expanding and Simplifying: x2+y2+2y+1=68x^2 + y^2 + 2y + 1 = 68 x2+y2+2y+168=0x^2 + y^2 + 2y + 1 - 68 = 0 x2+y2+2y67=0x^2 + y^2 + 2y - 67 = 0

General Form: x2+y2+2y67=0x^2 + y^2 + 2y - 67 = 0

Problem 5:

A circle whose center is at (6,8)(6, -8) with a diameter that is 6136\sqrt{13} units

  1. Radius Calculation: r=6132=313r = \frac{6\sqrt{13}}{2} = 3\sqrt{13}

  2. Standard Form: (x6)2+(y+8)2=(313)2(x - 6)^2 + (y + 8)^2 = (3\sqrt{13})^2 Simplifying: (x6)2+(y+8)2=913(x - 6)^2 + (y + 8)^2 = 9 \cdot 13 (x6)2+(y+8)2=117(x - 6)^2 + (y + 8)^2 = 117

  3. Expanding and Simplifying: (x6)2+(y+8)2=117(x - 6)^2 + (y + 8)^2 = 117 x212x+36+y2+16y+64=117x^2 - 12x + 36 + y^2 + 16y + 64 = 117 x2+y212x+16y+100117=0x^2 + y^2 - 12x + 16y + 100 - 117 = 0 x2+y212x+16y17=0x^2 + y^2 - 12x + 16y - 17 = 0

General Form: x2+y212x+16y17=0x^2 + y^2 - 12x + 16y - 17 = 0

Problem 6:

A circle whose center is at (5,0)(5,0) and passes through the point (9,3)(9,3)

  1. Radius Calculation: Using the distance formula: r=(95)2+(30)2r = \sqrt{(9 - 5)^2 + (3 - 0)^2} r=42+32r = \sqrt{4^2 + 3^2} r=16+9r = \sqrt{16 + 9} r=25r = \sqrt{25} r=5r = 5

  2. Standard Form: (x5)2+(y0)2=52(x - 5)^2 + (y - 0)^2 = 5^2 Simplifying: (x5)2+y2=25(x - 5)^2 + y^2 = 25

  3. Expanding and Simplifying: (x5)2+y2=25(x - 5)^2 + y^2 = 25 x210x+25+y2=25x^2 - 10x + 25 + y^2 = 25 x2+y210x+2525=0x^2 + y^2 - 10x + 25 - 25 = 0 x2+y210x=0x^2 + y^2 - 10x = 0

General Form: x2+y210x=0x^2 + y^2 - 10x = 0

Do you want more details or have any questions?

Here are some related questions to explore further:

  1. How do you derive the general form from the standard form of a circle?
  2. What are the key differences between the general and standard forms of a circle's equation?
  3. How can you find the center and radius from a circle's general equation?
  4. How do you calculate the radius of a circle given the diameter?
  5. What is the distance formula used for in circle problems?
  6. How can you determine if a point lies on a circle given its equation?
  7. What steps are involved in converting a circle's equation from standard to general form?
  8. How does changing the center of a circle affect its equation?

Tip: Always verify your final circle equation by plugging in the center coordinates and radius back into the standard form to check for consistency.

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Math Problem Analysis

Mathematical Concepts

Circle equations
Geometry

Formulas

Distance formula

Theorems

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Suitable Grade Level

Grades 10-12