To find the current flowing through resistor $R3$, we can analyze the circuit using Ohm's law and the rules for parallel circuits.

Given Data:

• $V_s = 36V$
• $R_1 = 56 \text{ k}\Omega$
• $R_2 = 75 \text{ k}\Omega$
• $R_3 = 91 \text{ k}\Omega$

Since all three resistors are in parallel, the voltage across each resistor is equal to the source voltage $V_s = 36V$.

Step 1: Calculate the Current Through $R3$

Using Ohm’s law, the current through $R3$ is given by: $I_{R3} = \frac{V_s}{R3}$ Substitute the values: $I_{R3} = \frac{36V}{91 \times 10^3 \Omega} = \frac{36}{91000} = 0.0003956 \, \text{A} = 395.6 \, \mu\text{A}$

Answer:

The correct answer is 395.6 µA.

Would you like more details on this solution or have any questions?

Here are some related questions for further practice:

1. How would you calculate the total current supplied by the source in this parallel circuit?
2. What would happen to the current through $R3$ if the resistance of $R3$ was increased?
3. How can you calculate the equivalent resistance of the circuit?
4. How would the current through $R3$ change if $V_s$ were 24V instead of 36V?
5. What is the power dissipated by $R3$ in this circuit?

Tip: In parallel circuits, the voltage across each branch is equal to the source voltage.