The given circuit shows a combination of resistors with values:

• $E_T = 120 \, \text{V}$ (total voltage),
• $I_T = 200 \, \text{mA} = 0.2 \, \text{A}$ (total current),
• $R_1 = 1 \, \text{k}\Omega = 1000 \, \Omega$,
• $R_3 = 5.6 \, \text{k}\Omega = 5600 \, \Omega$,
• $R_2 = ?$ (unknown).

Step 1: Determine the total resistance of the circuit

Using Ohm's law:

$R_T = \frac{E_T}{I_T} = \frac{120 \, \text{V}}{0.2 \, \text{A}} = 600 \, \Omega$

Step 2: Understand the circuit configuration

The circuit shows $R_1$ in series with a parallel combination of $R_2$ and $R_3$.

• Total resistance, $R_T$, is the sum of the series resistance $R_1$ and the equivalent resistance of $R_2$ and $R_3$ in parallel ($R_{23}$):

$R_T = R_1 + R_{23}$

Step 3: Solve for $R_{23}$

$R_{23} = R_T - R_1 = 600 \, \Omega - 1000 \, \Omega = -400 \, \Omega$

This negative result indicates there was an error in interpretation