The equation you're using is:

$v = u + at$

Where:

• $v = 20 \, \text{m/s}$ (final velocity),
• $u = 0 \, \text{m/s}$ (initial velocity, since the car starts from rest),
• $t = 5 \, \text{seconds}$ (time),
• $a$ is the acceleration (which we need to find).

Now, plug the values into the equation:

$20 = 0 + a \times 5$

Simplify:

$20 = 5a$

Solving for $a$:

$a = \frac{20}{5} = 4 \, \text{m/s}^2$

So, the car's acceleration is 4 m/s².

Would you like more details or have any questions?

Here are 5 related questions to deepen your understanding:

1. What would the acceleration be if the final velocity was 30 m/s in 5 seconds?
2. How would the time change if the acceleration was doubled?
3. What distance would the car have traveled during the 5 seconds?
4. How would the acceleration change if the car started with an initial velocity of 5 m/s?
5. How can you calculate the car's average velocity during the acceleration?

Tip: When dealing with constant acceleration, it's often useful to also apply other kinematic equations to find quantities like distance or average velocity.