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The problem from the image appears to read:

**"27. If the length of a rectangular field is \( (x + 2) \) meters and the width is 6 meters, what is its area?"**

### Solution:

The formula for the area \( A \) of a rectangle is:

\[
A = \text{length} \times \text{width}
\]

Here, the length is \( (x + 2) \) meters, and the width is \( 6 \) meters. Therefore, the area \( A \) is:

\[
A = (x + 2) \times 6
\]

Distribute the 6:

\[
A = 6(x + 2) = 6x + 12
\]

Thus, the area of the rectangular field is:

\[
A = 6x + 12 \, \text{square meters}.
\]

Would you like further details or have any other questions?

Here are 5 related questions for further practice:

1. What is the perimeter of the rectangular field given the length and width?
2. If \( x = 4 \), what is the exact area of the field?
3. How would the area change if the width were doubled?
4. Find the area if the length was \( (2x + 3) \) meters and the width was \( 8 \) meters.
5. What is the area when \( x = 0 \)?

**Tip:** When finding the area of shapes, always ensure to use the correct units of measurement, typically square units for area!

If the length of a rectangular field is (x + 2) meters and the width is 6 meters, what is its area?

Learn how to find the area of a rectangular field where the length is (x + 2) meters and the width is 6 meters. This problem involves using the area formula for rectangles and applying the distributive property. Suitable for students in Grades 6-8.

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