Math Problem Statement

If the length of a rectangular field is (x + 2) meters and the width is 6 meters, what is its area?

Solution

The problem from the image appears to read:

"27. If the length of a rectangular field is (x+2)(x + 2) meters and the width is 6 meters, what is its area?"

Solution:

The formula for the area AA of a rectangle is:

A=length×widthA = \text{length} \times \text{width}

Here, the length is (x+2)(x + 2) meters, and the width is 66 meters. Therefore, the area AA is:

A=(x+2)×6A = (x + 2) \times 6

Distribute the 6:

A=6(x+2)=6x+12A = 6(x + 2) = 6x + 12

Thus, the area of the rectangular field is:

A=6x+12square meters.A = 6x + 12 \, \text{square meters}.

Would you like further details or have any other questions?

Here are 5 related questions for further practice:

  1. What is the perimeter of the rectangular field given the length and width?
  2. If x=4x = 4, what is the exact area of the field?
  3. How would the area change if the width were doubled?
  4. Find the area if the length was (2x+3)(2x + 3) meters and the width was 88 meters.
  5. What is the area when x=0x = 0?

Tip: When finding the area of shapes, always ensure to use the correct units of measurement, typically square units for area!

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Rectangles
Distributive Property

Formulas

Area of a rectangle A = length × width
Distributive Property: a(b + c) = ab + ac

Theorems

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Suitable Grade Level

Grades 6-8