Math Problem Statement
Solution
The problem in the image involves a square made from thin wire, with a perimeter of 60 cm, and asks three questions:
- (a) The area of the square.
- (b) The area of a rectangle made with the wire, where the length is twice its width.
- (c) The number of smaller squares that can be made from the wire, each with an area of 4 square centimeters.
Let's solve each part.
Part (a) - Area of the Square
The perimeter of the square is given as 60 cm. The perimeter of a square is calculated by:
Substitute the given perimeter:
The area of a square is:
So, the area of the square is 225 cm².
Part (b) - Area of the Rectangle
The length of the rectangle is twice its width. Let's denote:
- = width
- = length
The perimeter of a rectangle is:
Since the wire is 60 cm long (the perimeter of the rectangle):
So, the width is 10 cm and the length is:
The area of the rectangle is:
So, the area of the rectangle is 200 cm².
Part (c) - Number of Smaller Squares
Each smaller square has an area of 4 cm². The area of each small square is related to its side length by:
We need to find how many smaller squares can be made from the total wire area. The total area of the square formed from the wire is 225 cm² (from part (a)).
Now, divide the total area by the area of each small square:
Since we can only have whole squares, we round down to 56 smaller squares.
Would you like more details on any part of this solution?
Related Questions:
- What is the relationship between the perimeter and area of a square?
- How does changing the dimensions of a rectangle while keeping the perimeter constant affect its area?
- What is the formula for calculating the perimeter of any rectangle or square?
- How do you calculate the area of a square or rectangle given the side lengths?
- How can you determine the number of smaller shapes that can fit into a larger one?
Tip:
When calculating areas, always make sure to double-check the units and ensure you're consistent throughout the problem!
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Math Problem Analysis
Mathematical Concepts
Geometry
Perimeter
Area
Rectangles
Squares
Formulas
Perimeter of a square: P = 4 * side
Area of a square: A = side^2
Perimeter of a rectangle: P = 2 * (length + width)
Area of a rectangle: A = length * width
Theorems
Basic properties of squares and rectangles
Suitable Grade Level
Grade 6-8