Find the angle whose supplement is 10° more than twice it's complement 

Let the unknown angle be \( x \) degrees.

### Step 1: Define the relationships
- The **supplement** of \( x \) is \( 180^\circ - x \).
- The **complement** of \( x \) is \( 90^\circ - x \).

According to the problem, the supplement is 10° more than twice its complement:

\[
180^\circ - x = 2(90^\circ - x) + 10^\circ
\]

### Step 2: Solve the equation
Expand and simplify the equation:

\[
180^\circ - x = 180^\circ - 2x + 10^\circ
\]

Next, simplify further:

\[
180^\circ - x = 190^\circ - 2x
\]

### Step 3: Isolate \( x \)
Add \( 2x \) to both sides:

\[
180^\circ + x = 190^\circ
\]

Subtract \( 180^\circ \) from both sides:

\[
x = 10^\circ
\]

### Final Answer:
The angle \( x \) is \( 10^\circ \).

Would you like more details, or do you have any other questions?

Here are 5 related questions:
1. What is the supplement of an angle?
2. How do you find the complement of an angle?
3. What would the angle be if the supplement was 20° more than twice its complement?
4. How does the concept of an angle's supplement and complement apply in geometry?
5. What happens if the angle is 45°? What are its supplement and complement?

**Tip:** Always double-check your equations when dealing with supplements and complements, as small mistakes can lead to incorrect results.

Learn how to find the angle whose supplement is 10° more than twice its complement with a detailed step-by-step solution. This problem involves angles, supplements, complements, and basic equations. Suitable for students in Grades 7-9.

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