Math Problem Statement

Find the angle whose supplement is 10° more than twice it's complement

Solution

Let the unknown angle be xx degrees.

Step 1: Define the relationships

  • The supplement of xx is 180x180^\circ - x.
  • The complement of xx is 90x90^\circ - x.

According to the problem, the supplement is 10° more than twice its complement:

180x=2(90x)+10180^\circ - x = 2(90^\circ - x) + 10^\circ

Step 2: Solve the equation

Expand and simplify the equation:

180x=1802x+10180^\circ - x = 180^\circ - 2x + 10^\circ

Next, simplify further:

180x=1902x180^\circ - x = 190^\circ - 2x

Step 3: Isolate xx

Add 2x2x to both sides:

180+x=190180^\circ + x = 190^\circ

Subtract 180180^\circ from both sides:

x=10x = 10^\circ

Final Answer:

The angle xx is 1010^\circ.

Would you like more details, or do you have any other questions?

Here are 5 related questions:

  1. What is the supplement of an angle?
  2. How do you find the complement of an angle?
  3. What would the angle be if the supplement was 20° more than twice its complement?
  4. How does the concept of an angle's supplement and complement apply in geometry?
  5. What happens if the angle is 45°? What are its supplement and complement?

Tip: Always double-check your equations when dealing with supplements and complements, as small mistakes can lead to incorrect results.