Math Problem Statement

if m/EBH=(6x+12) and m/HBC= (8x-10) find m/EBH

Solution

To solve for m/EBHm/\angle EBH, given the following information:

  • m/EBH=6x+12m/\angle EBH = 6x + 12
  • m/HBC=8x10m/\angle HBC = 8x - 10

We need additional information about the relationship between these angles. If these two angles are somehow related (for example, they form a linear pair, are complementary, or supplementary), we can set up an equation to solve for xx.

Assuming m/EBHm/\angle EBH and m/HBCm/\angle HBC form a linear pair (meaning they are adjacent and sum to 180180^\circ), we can set up the following equation:

(6x+12)+(8x10)=180(6x + 12) + (8x - 10) = 180

Step-by-step solution:

  1. Combine like terms: 6x+12+8x10=1806x + 12 + 8x - 10 = 180 14x+2=18014x + 2 = 180

  2. Subtract 2 from both sides: 14x=17814x = 178

  3. Divide both sides by 14: x=17814=12.71x = \frac{178}{14} = 12.71

Now that we have x=12.71x = 12.71, we can substitute it back into the expression for m/EBHm/\angle EBH:

m/EBH=6x+12=6(12.71)+12=76.26+12=88.26m/\angle EBH = 6x + 12 = 6(12.71) + 12 = 76.26 + 12 = 88.26^\circ

Thus, m/EBH88.26m/\angle EBH \approx 88.26^\circ.

Do you need more details or have any questions?

Related Questions:

  1. What happens if m/EBHm/\angle EBH and m/HBCm/\angle HBC are complementary instead of forming a linear pair?
  2. How would the solution change if the sum of these angles is given to be 9090^\circ?
  3. Can you verify the relationship between the angles from a diagram if provided?
  4. What are other possible types of angle relationships in geometry?
  5. How do you solve similar problems involving different kinds of angles, such as vertical angles?

Tip:

Always look for key words that describe angle relationships, such as "linear pair," "complementary," or "supplementary." These words are crucial in setting up the correct equations for solving geometric problems.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Linear Pair of Angles

Formulas

Sum of angles in a linear pair: m/∠EBH + m/∠HBC = 180°

Theorems

Linear Pair Theorem

Suitable Grade Level

Grades 9-10