Math Problem Statement

In parallelogram ABCD, find the measure of angle A, where the angles are given as (6x + 20)° and (4x + 10)°.

Solution

Let me analyze the problem in the uploaded image.

The problem shows a parallelogram ABCDABCD, and the goal is to find the measure of angle AA, denoted as mAm \angle A. The two adjacent angles are given as:

  • A=(6x+20)\angle A = (6x + 20)^\circ
  • D=(4x+10)\angle D = (4x + 10)^\circ

Key Properties of a Parallelogram:

  1. Adjacent angles of a parallelogram are supplementary, i.e., their sum equals 180180^\circ:
    A+D=180\angle A + \angle D = 180^\circ

Steps to Solve:

  1. Use the supplementary property: (6x+20)+(4x+10)=180(6x + 20) + (4x + 10) = 180

  2. Simplify the equation: 10x+30=18010x + 30 = 180

  3. Solve for xx: 10x=150x=1510x = 150 \quad \Rightarrow \quad x = 15

  4. Substitute x=15x = 15 into mA=6x+20m \angle A = 6x + 20: mA=6(15)+20=90+20=110m \angle A = 6(15) + 20 = 90 + 20 = 110^\circ

Final Answer:

mA=110m \angle A = 110^\circ

Would you like further clarification or steps explained?

Here are 5 related questions to expand this topic:

  1. How do you calculate the measure of the other angles in the parallelogram?
  2. What are other properties of a parallelogram involving diagonals or opposite angles?
  3. How would the solution change if this were a rhombus?
  4. Can you derive a general formula for solving similar problems in parallelograms?
  5. What are the key differences between a parallelogram and a trapezium?

Tip: Always remember that adjacent angles in a parallelogram are supplementary while opposite angles are equal.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Properties of Parallelograms

Formulas

Sum of adjacent angles in a parallelogram: Angle A + Angle D = 180°

Theorems

Supplementary property of adjacent angles in a parallelogram

Suitable Grade Level

Grades 8-10