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In a parallelogram, opposite angles are equal, and consecutive (or adjacent) angles are supplementary, meaning their measures add up to 180°. This is because the internal angles of any parallelogram must satisfy this condition.

Given that \(\angle A = 99^\circ\), the adjacent angle \(\angle B\) must satisfy the following equation:

\[
\angle A + \angle B = 180^\circ
\]

Substituting the value of \(\angle A\):

\[
99^\circ + \angle B = 180^\circ
\]

Now, solving for \(\angle B\):

\[
\angle B = 180^\circ - 99^\circ = 81^\circ
\]

Thus, the measure of \(\angle B\) is \(81^\circ\) because adjacent angles in a parallelogram are supplementary.

### Suggested Response:
"The measure of \(\angle B\) must be \(81^\circ\) because in a parallelogram, adjacent angles are supplementary. Since \(\angle A = 99^\circ\), we subtract it from \(180^\circ\) to find \(\angle B = 81^\circ\)."

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Would you like any further details or clarifications on this? 

Here are 5 related questions to deepen your understanding:
1. How do you prove that adjacent angles in a parallelogram are supplementary?
2. What are the properties of a parallelogram regarding angles and sides?
3. If \(\angle B\) were given instead of \(\angle A\), how would you calculate \(\angle A\)?
4. What happens if the parallelogram is a rectangle? What would the angles be?
5. How would the problem change if the shape were a trapezoid instead of a parallelogram?

**Tip:** Always remember, in any quadrilateral, the sum of all interior angles is \(360^\circ\).

In parallelogram ABCD, the measure of angle A is 99°. Explain why the measure of adjacent angle B must be 81°.

Learn why the measure of angle B in a parallelogram must be 81° when angle A is given as 99°. Understand the geometric properties of parallelograms, focusing on the theorem that adjacent angles are supplementary, making this problem suitable for students in Grades 6-8.

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