Math Problem Statement

Solve

Use the values of a_1 and S_50 to find the value of a_50, given a_1 = 6 and S_50 = 6650.

Solution

From the image, the problem seems to ask you to find the value of a50a_{50} using the values of a1a_1 and S50S_{50}.

The given information appears to be:

  • a1=6a_1 = 6
  • S50=6650S_{50} = 6650
  • The formula for the sum of the first nn terms of an arithmetic series is Sn=n2(a1+an)S_n = \frac{n}{2} (a_1 + a_n).

Using this formula for S50S_{50}:

S50=502(a1+a50)S_{50} = \frac{50}{2} (a_1 + a_{50})

Substitute the given values a1=6a_1 = 6 and S50=6650S_{50} = 6650 into the equation:

6650=502(6+a50)6650 = \frac{50}{2} (6 + a_{50})

Now, let's solve for a50a_{50}.

6650=25(6+a50)6650 = 25 (6 + a_{50}) 665025=6+a50\frac{6650}{25} = 6 + a_{50} 266=6+a50266 = 6 + a_{50} a50=2666a_{50} = 266 - 6 a50=260a_{50} = 260

Thus, the value of a50a_{50} is 260.

Would you like a more detailed explanation of the steps or have any other questions?

Here are 5 related questions you can explore:

  1. How can you find the common difference in an arithmetic series?
  2. How would the formula change if this were a geometric series?
  3. What is the sum of the first 100 terms in this series?
  4. How can you derive the general term formula for an arithmetic sequence?
  5. What happens to the sum formula if nn becomes very large?

Tip: When solving for a term in an arithmetic series, always check whether you are working with a partial sum or individual terms to avoid confusion.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Series
Summation of Series

Formulas

S_n = (n/2)(a_1 + a_n)

Theorems

Sum of Arithmetic Series

Suitable Grade Level

Grades 9-12