To find the 10th term of an arithmetic sequence where the first term $a_1 = 32$ and the common difference $d = -6$, we can use the formula for the $n$th term:

$a_n = a_1 + (n - 1) \times d$

Step 1: Identify the values

• $a_1 = 32$
• $d = -6$
• $n = 10$

Step 2: Substitute the values into the formula

$a_{10} = 32 + (10 - 1) \times (-6)$ $a_{10} = 32 + 9 \times (-6)$ $a_{10} = 32 - 54$ $a_{10} = -22$

Final Answer

The 10th term of the sequence is $-22$.

Would you like to explore more on this topic or have any other questions?

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Here are five related questions:

1. What is the 15th term of this sequence?
2. How many terms are needed for the sequence to reach a value below $-50$?
3. What is the sum of the first 10 terms of this sequence?
4. How would the sequence change if the common difference was $-8$ instead of $-6$?
5. Can you find the 20th term of the sequence?

Tip: When working with negative common differences, remember that the sequence decreases over time.