Math Problem Statement

-4,-6,-8,...10th term an=a1+(n-1)d

Solution

To find the 10th term of the arithmetic sequence 4,6,8,-4, -6, -8, \dots, we'll use the formula for the nnth term of an arithmetic sequence:

an=a1+(n1)da_n = a_1 + (n - 1) \cdot d

Step 1: Identify the first term (a1a_1) and the common difference (dd)

  • The first term, a1a_1, is 4-4.
  • The common difference, dd, is found by subtracting the first term from the second term:

d=6(4)=6+4=2d = -6 - (-4) = -6 + 4 = -2

Step 2: Apply the formula to find the 10th term (a10a_{10})

Substitute a1=4a_1 = -4, d=2d = -2, and n=10n = 10 into the formula:

a10=4+(101)(2)a_{10} = -4 + (10 - 1) \cdot (-2)

a10=4+9(2)a_{10} = -4 + 9 \cdot (-2)

a10=418a_{10} = -4 - 18

a10=22a_{10} = -22

So, the 10th term of the sequence is 22-22.

Would you like more details or have any questions?

Related Questions:

  1. What is the general formula for the nnth term of any arithmetic sequence?
  2. How do you find the common difference if you're given any two terms in a sequence?
  3. What is the sum of the first 10 terms of this sequence?
  4. How can you determine if a sequence is arithmetic or geometric?
  5. Can an arithmetic sequence have a positive common difference?

Tip: The common difference in an arithmetic sequence can be positive or negative, affecting whether the sequence increases or decreases.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences

Formulas

Arithmetic sequence nth term formula

Theorems

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Suitable Grade Level

Grades 9-12