A sequence of numbers is written in such a way that is number is greater than the receiving number by three starting the sequence from -2, the 10th number of the sequence is

We are given a sequence where each number is 3 greater than the previous one, and the sequence starts at -2. This is an arithmetic sequence.

### Formula for the \(n\)-th term of an arithmetic sequence:
\[
a_n = a_1 + (n - 1) \cdot d
\]
Where:
- \(a_n\) is the \(n\)-th term,
- \(a_1 = -2\) (the first term),
- \(d = 3\) (the common difference),
- \(n\) is the term number.

We are asked to find the 10th term, so \(n = 10\).

### Substituting into the formula:
\[
a_{10} = -2 + (10 - 1) \cdot 3
\]
\[
a_{10} = -2 + 9 \cdot 3
\]
\[
a_{10} = -2 + 27
\]
\[
a_{10} = 25
\]

Thus, the 10th number of the sequence is **25**.

Would you like more details or have any questions?

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Here are 5 related questions:
1. What would the 20th term of this sequence be?
2. How do you find the sum of the first 10 terms of an arithmetic sequence?
3. Can you describe how the common difference affects the growth of the sequence?
4. What is the general formula to find any term in an arithmetic sequence?
5. How can we identify whether a sequence is arithmetic or not?

**Tip**: For any arithmetic sequence, the difference between consecutive terms remains constant, making it easy to predict future values.

A sequence of numbers is written in such a way that each number is greater than the preceding number by three, starting the sequence from -2. What is the 10th number of the sequence?

Learn how to find the 10th term of an arithmetic sequence where each number increases by 3, starting from -2. This problem covers core concepts in arithmetic sequences, including the formula for the nth term, and is suitable for Grades 6-8.

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