Math Problem Statement

False Position Method The following equations has a root in the indicated interval. Using False Position Method, generate the first four elements in the sequence that eventually converges to the root 2e^−x/2 + ln x = 1, (0.1,1)

Solution

The False Position Method (also called the Regula Falsi method) is a numerical method used to solve equations of the form f(x)=0f(x) = 0, where f(x)f(x) is a continuous function. It iteratively refines the estimate of the root based on the values of f(x)f(x) at two points that bracket the root.

Given equation:

2ex/2+ln(x)=12e^{-x/2} + \ln(x) = 1 We need to rewrite this equation in the form: f(x)=2ex/2+ln(x)1=0f(x) = 2e^{-x/2} + \ln(x) - 1 = 0

We are also given the interval (0.1,1)(0.1, 1), which means the root lies between these two values. Let's now apply the False Position Method to generate the first four approximations of the root.

Step 1: Calculate f(x)f(x) at the endpoints of the interval

We first evaluate the function f(x)f(x) at the endpoints x0=0.1x_0 = 0.1 and x1=1x_1 = 1.

1. Evaluate f(0.1)f(0.1):

f(0.1)=2e0.1/2+ln(0.1)1=2e0.05+ln(0.1)1f(0.1) = 2e^{-0.1/2} + \ln(0.1) - 1 = 2e^{-0.05} + \ln(0.1) - 1

2. Evaluate f(1)f(1):

f(1)=2e1/2+ln(1)1=2e0.5+01f(1) = 2e^{-1/2} + \ln(1) - 1 = 2e^{-0.5} + 0 - 1

Step 2: Calculate the first approximation x2x_2 using the False Position formula:

The False Position formula for the next approximation is: [ x_2 =

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Numerical Methods
False Position Method
Exponential Functions
Logarithmic Functions

Formulas

False Position Method formula: x_n = x1 - f(x1) * (x1 - x0) / (f(x1) - f(x0))
f(x) = 2e^(-x/2) + ln(x) - 1

Theorems

Intermediate Value Theorem

Suitable Grade Level

Undergraduate Mathematics or Numerical Methods