Math Problem Statement

factorise these

Factorise by first taking out a common factor.

Solution

Let’s factorise each expression by taking out the common factors.

Solutions

a) 2x2322x^2 - 32

  • Factor out 2:
    2(x216)2(x^2 - 16)
  • Further factorize x216x^2 - 16 as a difference of squares:
    2(x+4)(x4)2(x + 4)(x - 4)

b) 3x21083x^2 - 108

  • Factor out 3:
    3(x236)3(x^2 - 36)
  • Further factorize x236x^2 - 36:
    3(x+6)(x6)3(x + 6)(x - 6)

c) 4a21004a^2 - 100

  • Factor out 4:
    4(a225)4(a^2 - 25)
  • Further factorize a225a^2 - 25:
    4(a+5)(a5)4(a + 5)(a - 5)

d) 5y2205y^2 - 20

  • Factor out 5:
    5(y24)5(y^2 - 4)
  • Further factorize y24y^2 - 4:
    5(y+2)(y2)5(y + 2)(y - 2)

e) 24a26b224a^2 - 6b^2

  • Factor out 6:
    6(4a2b2)6(4a^2 - b^2)
  • Further factorize 4a2b24a^2 - b^2:
    6(2a+b)(2ab)6(2a + b)(2a - b)

f) 3x227y23x^2 - 27y^2

  • Factor out 3:
    3(x29y2)3(x^2 - 9y^2)
  • Further factorize x29y2x^2 - 9y^2:
    3(x+3y)(x3y)3(x + 3y)(x - 3y)

g) 8y21288y^2 - 128

  • Factor out 8:
    8(y216)8(y^2 - 16)
  • Further factorize y216y^2 - 16:
    8(y+4)(y4)8(y + 4)(y - 4)

h) 80p25q280p^2 - 5q^2

  • Factor out 5:
    5(16p2q2)5(16p^2 - q^2)
  • Further factorize 16p2q216p^2 - q^2:
    5(4p+q)(4pq)5(4p + q)(4p - q)

i) 4x2644x^2 - 64

  • Factor out 4:
    4(x216)4(x^2 - 16)
  • Further factorize x216x^2 - 16:
    4(x+4)(x4)4(x + 4)(x - 4)

j) 3x233x^2 - 3

  • Factor out 3:
    3(x21)3(x^2 - 1)
  • Further factorize x21x^2 - 1:
    3(x+1)(x1)3(x + 1)(x - 1)

k) 72p2272p^2 - 2

  • Factor out 2:
    2(36p21)2(36p^2 - 1)
  • Further factorize 36p2136p^2 - 1:
    2(6p+1)(6p1)2(6p + 1)(6p - 1)

l) 218x22 - 18x^2

  • Factor out 2:
    2(19x2)2(1 - 9x^2)
  • Further factorize 19x21 - 9x^2:
    2(1+3x)(13x)2(1 + 3x)(1 - 3x)

m) 8a218m28a^2 - 18m^2

  • Factor out 2:
    2(4a29m2)2(4a^2 - 9m^2)
  • Further factorize 4a29m24a^2 - 9m^2:
    2(2a+3m)(2a3m)2(2a + 3m)(2a - 3m)

n) 12520a2125 - 20a^2

  • Factor out 5:
    5(254a2)5(25 - 4a^2)
  • Further factorize 254a225 - 4a^2:
    5(5+2a)(52a)5(5 + 2a)(5 - 2a)

o) 200x218y2200x^2 - 18y^2

  • Factor out 2:
    2(100x29y2)2(100x^2 - 9y^2)
  • Further factorize 100x29y2100x^2 - 9y^2:
    2(10x+3y)(10x3y)2(10x + 3y)(10x - 3y)

p) 98m28n298m^2 - 8n^2

  • Factor out 2:
    2(49m24n2)2(49m^2 - 4n^2)
  • Further factorize 49m24n249m^2 - 4n^2:
    2(7m+2n)(7m2n)2(7m + 2n)(7m - 2n)

Would you like further clarification on any of these steps?


Related Questions:

  1. How do you determine if a quadratic expression can be factored further?
  2. What is the difference between factoring out a common factor and factoring a difference of squares?
  3. How do you identify the greatest common factor in polynomials with multiple terms?
  4. What is the procedure for factoring a trinomial versus a binomial?
  5. How can factorization be applied in solving algebraic equations?

Tip:

Always check if the terms share a greatest common factor before attempting to use other factoring methods. This step can simplify the process significantly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Factorization
Difference of Squares

Formulas

Common Factor Formula: Take out the common factor first
Difference of Squares Formula: a^2 - b^2 = (a + b)(a - b)

Theorems

Difference of Squares Theorem

Suitable Grade Level

Grades 8-10