The expression \( 4s^2 - 25 \) is a difference of squares. The general formula for factoring a difference of squares is:

\[
a^2 - b^2 = (a - b)(a + b)
\]

In this case:

- \( a^2 = 4s^2 \), so \( a = 2s \)
- \( b^2 = 25 \), so \( b = 5 \)

Thus, the factorization of \( 4s^2 - 25 \) is:

\[
(2s - 5)(2s + 5)
\]

Would you like more details or have any questions?

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Here are 8 related questions:

1. How do you factor \( x^2 - 49 \)?
2. What is the difference of squares formula?
3. How do you factor \( 9y^2 - 16 \)?
4. What are perfect square trinomials, and how do you factor them?
5. How do you factor \( 36a^2 - 1 \)?
6. How do you factor a sum of squares?
7. How can you identify if a polynomial is a difference of squares?
8. What is the relationship between factoring and solving quadratic equations?

**Tip:** Always check if a quadratic expression is a difference of squares by confirming that both terms are perfect squares.

Learn how to factor the expression 4s^2 - 25 using the difference of squares formula. This problem covers key algebraic concepts, including factoring, quadratic equations, and the difference of squares. Suitable for students in Grades 7-9.

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