The given expression is \( x^2 - 25 \).

This is a **difference of squares**, which can be factored using the formula:

\[
a^2 - b^2 = (a - b)(a + b)
\]

In your case, \( a = x \) and \( b = 5 \) because \( 25 = 5^2 \). Thus, we can factor the expression:

\[
x^2 - 25 = (x - 5)(x + 5)
\]

Would you like more details or explanations?

Here are 5 related questions to deepen your understanding:
1. How would you factor \( x^2 - 49 \)?
2. Can you solve the equation \( x^2 - 25 = 0 \)?
3. What is the general formula for factoring a difference of squares?
4. How does factoring help solve quadratic equations?
5. What happens when you try to factor \( x^2 + 25 \), which is a sum of squares?

**Tip:** Always check if an expression is a difference of squares when both terms are perfect squares!

Learn how to factor the difference of squares in the expression x^2 - 25. This example demonstrates the application of the difference of squares theorem, where a^2 - b^2 = (a - b)(a + b). Suitable for students in Grades 8-10.

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