To express the given expression in the form 3n2m, let's work through each term step by step.
Given Expression:
8(32)4−4(32)5+2(32)6+6(32)7
Step 1: Expand Each Term
-
8(32)4
8⋅3424=818⋅16=81128
-
−4(32)5
−4⋅3525=−4⋅24332=−243128
-
2(32)6
2⋅3626=2⋅72964=729128
-
6(32)7
6⋅3727=6⋅2187128=2187768
Step 2: Combine the Terms
Combine all these fractions together:
81128−243128+729128+2187768
Step 3: Express as 3n2m
Notice that each term has a factor of 27 (or 128), so we can factor out 37128 from the expression:
37128(812187−2432187+7292187+6)
Now simplify the expression inside the parentheses:
812187=27,2432187=9,7292187=3
Expression becomes: 27−9+3+6=27
Thus, the entire expression simplifies to:
37128⋅27=37128⋅33=34128=3427
Final Answer:
3427
Summary:
The given expression simplifies to 3427.
Would you like more details or have any questions?
Here are five related questions for practice:
- Simplify 16(52)3−4(52)4+(52)5.
- Express 36×22−34×24 as a single power of 3n2m.
- How would you simplify 3528−3427+3326?
- Factor x4−4x2+4 completely.
- Express (43)3−(43)5+(43)7 as a single fraction.
Tip: When simplifying complex algebraic expressions, look for common factors that can be factored out to make the process easier.