Math Problem Statement

Write the complex number in exponential and trigonometric form z = 4+6i/1-5i

Solution

To express the complex number z=4+6i15iz = \frac{4 + 6i}{1 - 5i} in exponential and trigonometric forms, we'll follow these steps:

Step 1: Simplify the Complex Number

First, let's simplify zz by multiplying the numerator and denominator by the conjugate of the denominator:

z=4+6i15i×1+5i1+5iz = \frac{4 + 6i}{1 - 5i} \times \frac{1 + 5i}{1 + 5i}

z=(4+6i)(1+5i)(15i)(1+5i)z = \frac{(4 + 6i)(1 + 5i)}{(1 - 5i)(1 + 5i)}

The denominator simplifies using the difference of squares:

(15i)(1+5i)=12(5i)2=125(1)=1+25=26(1 - 5i)(1 + 5i) = 1^2 - (5i)^2 = 1 - 25(-1) = 1 + 25 = 26

Now, let's expand the numerator:

(4+6i)(1+5i)=4×1+4×5i+6i×1+6i×5i(4 + 6i)(1 + 5i) = 4 \times 1 + 4 \times 5i + 6i \times 1 + 6i \times 5i

=4+20i+6i+30i2=4+26i+30(1)=4+26i30=26+26i= 4 + 20i + 6i + 30i^2 = 4 + 26i + 30(-1) = 4 + 26i - 30 = -26 + 26i

So, the complex number zz simplifies to:

z=26+26i26=1+iz = \frac{-26 + 26i}{26} = -1 + i

Step 2: Convert to Trigonometric Form

The trigonometric form of a complex number z=a+biz = a + bi is given by:

z=r(cosθ+isinθ)z = r(\cos \theta + i \sin \theta)

Where rr is the magnitude (modulus) of zz and θ\theta is the argument (angle) of zz.

  1. Calculate the magnitude rr:

r=a2+b2=(1)2+12=1+1=2r = \sqrt{a^2 + b^2} = \sqrt{(-1)^2 + 1^2} = \sqrt{1 + 1} = \sqrt{2}

  1. Calculate the argument θ\theta:

θ=tan1(ba)=tan1(11)=tan1(1)\theta = \tan^{-1}\left(\frac{b}{a}\right) = \tan^{-1}\left(\frac{1}{-1}\right) = \tan^{-1}(-1)

Since z=1+iz = -1 + i lies in the second quadrant (negative real part, positive imaginary part), the argument is:

θ=ππ4=3π4\theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4}

Thus, the trigonometric form is:

z=2(cos3π4+isin3π4)z = \sqrt{2} \left( \cos\frac{3\pi}{4} + i\sin\frac{3\pi}{4} \right)

Step 3: Convert to Exponential Form

The exponential form of a complex number is:

z=reiθz = r e^{i\theta}

Substituting the values we found:

z=2ei3π4z = \sqrt{2} e^{i\frac{3\pi}{4}}

Final Answer

The complex number z=4+6i15iz = \frac{4 + 6i}{1 - 5i} in:

  • Trigonometric form: 2(cos3π4+isin3π4)\sqrt{2} \left( \cos\frac{3\pi}{4} + i\sin\frac{3\pi}{4} \right)
  • Exponential form: 2ei3π4\sqrt{2} e^{i\frac{3\pi}{4}}

Would you like further details or explanations?


Here are some related questions to explore:

  1. How do you multiply two complex numbers in exponential form?
  2. What is the geometric interpretation of the argument θ\theta in the complex plane?
  3. How do you find the conjugate of a complex number in trigonometric form?
  4. How does the magnitude of a complex number change under multiplication?
  5. What is the relationship between polar and exponential forms of complex numbers?
  6. How can you derive Euler's formula from the trigonometric form of a complex number?
  7. What happens to the angle θ\theta when you take the reciprocal of a complex number?
  8. How do you solve complex equations involving both exponential and trigonometric forms?

Tip: When working with complex numbers, always pay attention to the quadrant in which the complex number lies to determine the correct argument θ\theta.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Trigonometry
Exponential Form

Formulas

Complex number division using conjugates
Trigonometric form of a complex number
Exponential form of a complex number

Theorems

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Suitable Grade Level

Advanced High School