Math Problem Statement

Suppose a fish population is currently 6000 and 5 years later the population is 18000. Use the explicit exponential model Pn=Po(1+r)^n to find the rate of growth.

Solution

The explicit exponential growth model is given by:

Pn=P0(1+r)nP_n = P_0 (1 + r)^n

Where:

  • PnP_n is the population after nn years,
  • P0P_0 is the initial population,
  • rr is the rate of growth (which we are trying to find),
  • nn is the number of years.

Given:

  • Initial population P0=6000P_0 = 6000,
  • Population after 5 years P5=18000P_5 = 18000,
  • Time n=5n = 5 years.

Step 1: Plug in the values into the formula

18000=6000(1+r)518000 = 6000 (1 + r)^5

Step 2: Solve for rr

  1. Divide both sides by 6000:

3=(1+r)53 = (1 + r)^5

  1. Take the fifth root of both sides to get rid of the exponent:

(1+r)=315(1 + r) = 3^{\frac{1}{5}}

  1. Calculate 3153^{\frac{1}{5}}:

1+r1.24571 + r \approx 1.2457

  1. Subtract 1 from both sides:

r0.2457r \approx 0.2457

Thus, the growth rate rr is approximately 0.2457, or 24.57%.

Would you like more details on any step or have further questions?

Here are 5 questions to expand on this concept:

  1. How can you verify the exponential model results with actual data?
  2. What happens to the population growth if the rate rr changes?
  3. How would you model a population decline instead of growth?
  4. What role does the number of years nn play in exponential models?
  5. How can this model apply to real-world scenarios other than population?

Tip: In exponential growth, small changes in the growth rate can lead to large differences over time.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Algebra

Formulas

Pn = Po(1 + r)^n

Theorems

Exponential Growth Model

Suitable Grade Level

Grades 9-12