Math Problem Statement

In 2005 the population of a district was
35 , 700 with a continuous annual growth rate of approximately
4 % , what will the population be in 2030 according to the exponential growth function?

Round the answer to the nearest whole number, do not include the unit in your answer.

Solution

The exponential growth formula is:
P(t)=P0ertP(t) = P_0 \cdot e^{rt} where:

  • P(t)P(t) is the population at time tt,
  • P0P_0 is the initial population (35,700 in 2005),
  • rr is the continuous annual growth rate (4% = 0.04),
  • tt is the time in years from the initial year (2030 - 2005 = 25 years),
  • ee is the base of the natural logarithm (2.718\approx 2.718).

Step-by-Step Calculation:

  1. Identify the known values:

    • P0=35,700P_0 = 35,700
    • r=0.04r = 0.04
    • t=25t = 25
  2. Plug the values into the formula: P(25)=35,700e0.0425P(25) = 35,700 \cdot e^{0.04 \cdot 25}

  3. Simplify the exponent: 0.0425=10.04 \cdot 25 = 1 So, the equation becomes: P(25)=35,700e1P(25) = 35,700 \cdot e^1

  4. Evaluate e1e^1: e12.718e^1 \approx 2.718

  5. Calculate the population: P(25)=35,7002.71897,051P(25) = 35,700 \cdot 2.718 \approx 97,051

Final Answer:

97,05197,051


Would you like more details or have any questions?
Here are 5 related questions you might find helpful:

  1. What happens if the growth rate changes each year?
  2. How does continuous growth compare to simple growth?
  3. What is the formula for compound interest, and how is it similar to population growth?
  4. How does doubling time relate to exponential growth?
  5. How can we determine the year when the population will hit 1,000,000?

Tip: Continuous growth models assume that the change occurs infinitely frequently, making them more accurate for biological or economic processes.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Continuous Growth

Formulas

P(t) = P_0 * e^(rt)

Theorems

Exponential Growth Theorem

Suitable Grade Level

Grades 10-12