Math Problem Statement

If you throw exactly two heads in three tosses of a coin you win $55 . If not, you pay me $28 .

Step 1 of 2 : Find the expected value of the proposition. Round your answer to two decimal places. Losses must be expressed as negative values.

Solution

To calculate the expected value of the proposition, we need to account for all possible outcomes and their respective probabilities.

Step 1: Determine the possible outcomes

You are tossing a coin three times, and there are 8 possible outcomes (since each toss has two possible results: heads (H) or tails (T)).

The possible outcomes for three coin tosses are:

  • HHH
  • HHT
  • HTH
  • HTT
  • THH
  • THT
  • TTH
  • TTT

Out of these, you win $55 if exactly two heads appear. The outcomes with exactly two heads are:

  • HHT
  • HTH
  • THH

So, there are 3 favorable outcomes (two heads).

Step 2: Calculate the probabilities

  • The probability of getting exactly two heads is the number of favorable outcomes (3) divided by the total number of outcomes (8), so: P(exactly 2 heads)=38P(\text{exactly 2 heads}) = \frac{3}{8}

  • The probability of not getting exactly two heads is the complement of the previous probability, so: P(not exactly 2 heads)=1P(exactly 2 heads)=138=58P(\text{not exactly 2 heads}) = 1 - P(\text{exactly 2 heads}) = 1 - \frac{3}{8} = \frac{5}{8}

Step 3: Calculate the expected value

The expected value (EV) is calculated by multiplying each outcome by its probability and then summing those values:

EV=(Win Amount×P(exactly 2 heads)))+(Loss Amount×P(not exactly 2 heads)))\text{EV} = \left(\text{Win Amount} \times P(\text{exactly 2 heads}))\right) + \left(\text{Loss Amount} \times P(\text{not exactly 2 heads}))\right)

Substitute the values: EV=(55×38)+(28×58)\text{EV} = (55 \times \frac{3}{8}) + (-28 \times \frac{5}{8}) EV=16581408\text{EV} = \frac{165}{8} - \frac{140}{8} EV=258\text{EV} = \frac{25}{8} EV=3.125\text{EV} = 3.125

Step 4: Round the result

The expected value is $3.13 (rounded to two decimal places).

Final Answer:

The expected value of the proposition is $3.13.


Would you like a more detailed explanation or have any questions about this process?

Here are some related questions for further exploration:

  1. What is the probability of getting exactly 1 head in 3 tosses of a coin?
  2. How do you calculate the expected value in a situation with multiple outcomes?
  3. What happens to the expected value if the win amount increases?
  4. How would you calculate the expected value for a game with more than two possible outcomes?
  5. How can you use the expected value to determine whether a game is fair?

Tip: When calculating expected value, always ensure that you account for the probability of all possible outcomes and their respective payoffs, including any losses!

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Math Problem Analysis

Mathematical Concepts

Probability
Expected Value
Combinatorics

Formulas

Expected Value formula: EV = (Win Amount × P(Win)) + (Loss Amount × P(Loss))

Theorems

Probability of independent events
Complementary probability

Suitable Grade Level

Grades 9-12