Math Problem Statement

Use the Laws of Logarithms to expand the expression. log

x5

y

z5

Solution

To expand the expression log(x5yz5)\log\left(\frac{x^5}{y \cdot z^5}\right), we can use the laws of logarithms. Here’s the step-by-step process:

Step 1: Apply the Quotient Rule

The Quotient Rule states that log(AB)=log(A)log(B)\log\left(\frac{A}{B}\right) = \log(A) - \log(B).

So, log(x5yz5)=log(x5)log(yz5)\log\left(\frac{x^5}{y \cdot z^5}\right) = \log(x^5) - \log(y \cdot z^5)

Step 2: Apply the Product Rule

The Product Rule states that log(AB)=log(A)+log(B)\log(A \cdot B) = \log(A) + \log(B).

Thus, log(x5)log(yz5)=log(x5)(log(y)+log(z5))\log(x^5) - \log(y \cdot z^5) = \log(x^5) - (\log(y) + \log(z^5))

Simplifying further, =log(x5)log(y)log(z5)= \log(x^5) - \log(y) - \log(z^5)

Step 3: Apply the Power Rule

The Power Rule states that log(Ak)=klog(A)\log(A^k) = k \cdot \log(A).

Applying this to each term with an exponent: =5log(x)log(y)5log(z)= 5 \cdot \log(x) - \log(y) - 5 \cdot \log(z)

Final Answer

The expanded form of the expression is: 5log(x)log(y)5log(z)5 \cdot \log(x) - \log(y) - 5 \cdot \log(z)

Would you like further clarification on any steps or details?


Here are some related questions:

  1. How would you expand log(a3bc2d4)\log\left(\frac{a^3 b}{c^2 d^4}\right)?
  2. Can you simplify log(x2y3z4)\log(x^2 y^3 z^4) using the laws of logarithms?
  3. How would you approach expanding ln(m7np2)\ln\left(\frac{m^7}{n \cdot p^2}\right) with natural logarithms?
  4. What are the differences between using logarithms with base 10 and base ee?
  5. How does changing the base of a logarithm affect the expansion process?

Tip: Remember that the laws of logarithms—Product, Quotient, and Power—are essential tools for simplifying complex logarithmic expressions.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Laws of Logarithms
Quotient Rule
Product Rule
Power Rule

Formulas

log(A/B) = log(A) - log(B)
log(A * B) = log(A) + log(B)
log(A^k) = k * log(A)

Theorems

Quotient Rule
Product Rule
Power Rule

Suitable Grade Level

Grades 9-12